Free Essays on Frequency Distribution

FREQUENCY DISTRIBUTION I. Identify the problem A randomly selected group of students in a class of 35 was asked how much allowance is given to them on a per day basis. The objective is to assess how much the average student gets on a daily basis, find how many of these students fall within a specified class interval using a frequency table, and how much the majority of the students get per day. II. Data: 100 200 300 500 100 200 250 450 300 700 250 350 200 250 100 500 200 150 150 150 150 150 300 350 250 250 300 350 250 250 400 350 400 300 400 Allowances per day of a group of 35 students studying at DLSU (in Php) III. Set-up the frequency table Class interval: =1 + 3.322log35 =6.12  » 6 Class size: =(700 – 100)/6 =100 Frequency Table Class Limits Class Mark Class Frequency Cum. Frequency 100-199 149.5 8 8 200-299 249.5 11 19 300-399 349.5 9 28 400-499 449.5 4 32 500-699 549.5 2 34 700-799 749.5 1 35 IV. Computations for descriptive statistics Mean: =(8)(149.5) + (11)(249.5) + (9)(349.5) + (4)(449.5) + (2)(549.5) + (1)(749.5) 35 =Php 306.63 Median: Median class is 200-299 =200 + 100{ [ (35/2) – 8 ] / 11 } =Php 286.36 Mode: Php 250.00 Measures of Variability: a. Average Deviation = (8)|49.5-306.63| + (11)|249.5-306.63| (9)|349.5-306.63| (4)|449.5-306.63| + (2)|549.5-306.63| (1)|749.5-306.63| 3771.39 = 3771.39/35 =Php 107.54 b. Variance/Standard Deviation Class Limits Class Mark Class Frequency fixi2 fixi 100-199 149.5 8 178,802 1,196 200-299 249.5 11 684,752.75 2,744.5 300-399 349.5 9 1,099,352.25 3,145.5 400-499 449.5 4 808,201 1,798 500-699 549.5 2 603,900.5 1,099 700-799 749.5 1 561,750.25 749.5 nà ¥ fixi2 = 35(3,936,758.75) = 137,786,556.25 (à ¥fixi)2 = (10,732.50)2 = 115,186,556.25 s2 = 137,786,556.25 - 115,186,55... Free Essays on Frequency Distribution Free Essays on Frequency Distribution FREQUENCY DISTRIBUTION I. Identify the problem A randomly selected group of students in a class of 35 was asked how much allowance is given to them on a per day basis. The objective is to assess how much the average student gets on a daily basis, find how many of these students fall within a specified class interval using a frequency table, and how much the majority of the students get per day. II. Data: 100 200 300 500 100 200 250 450 300 700 250 350 200 250 100 500 200 150 150 150 150 150 300 350 250 250 300 350 250 250 400 350 400 300 400 Allowances per day of a group of 35 students studying at DLSU (in Php) III. Set-up the frequency table Class interval: =1 + 3.322log35 =6.12  » 6 Class size: =(700 – 100)/6 =100 Frequency Table Class Limits Class Mark Class Frequency Cum. Frequency 100-199 149.5 8 8 200-299 249.5 11 19 300-399 349.5 9 28 400-499 449.5 4 32 500-699 549.5 2 34 700-799 749.5 1 35 IV. Computations for descriptive statistics Mean: =(8)(149.5) + (11)(249.5) + (9)(349.5) + (4)(449.5) + (2)(549.5) + (1)(749.5) 35 =Php 306.63 Median: Median class is 200-299 =200 + 100{ [ (35/2) – 8 ] / 11 } =Php 286.36 Mode: Php 250.00 Measures of Variability: a. Average Deviation = (8)|49.5-306.63| + (11)|249.5-306.63| (9)|349.5-306.63| (4)|449.5-306.63| + (2)|549.5-306.63| (1)|749.5-306.63| 3771.39 = 3771.39/35 =Php 107.54 b. Variance/Standard Deviation Class Limits Class Mark Class Frequency fixi2 fixi 100-199 149.5 8 178,802 1,196 200-299 249.5 11 684,752.75 2,744.5 300-399 349.5 9 1,099,352.25 3,145.5 400-499 449.5 4 808,201 1,798 500-699 549.5 2 603,900.5 1,099 700-799 749.5 1 561,750.25 749.5 nà ¥ fixi2 = 35(3,936,758.75) = 137,786,556.25 (à ¥fixi)2 = (10,732.50)2 = 115,186,556.25 s2 = 137,786,556.25 - 115,186,55...